Calculate the power output of a ${}_{92}^{235}U$ reactor, if it takes $30 \, \text{days}$ to consume $2 \, \text{kg}$ of fuel, and if each fission releases $185 \, \text{MeV}$ of usable energy. (Given: Avogadro's number $= 6 \times 10^{23} \, \text{mol}^{-1}$) .......... $\text{MW}$ (in $.3$)

  • A
    $56$
  • B
    $60$
  • C
    $58$
  • D
    $54$

Explore More

Similar Questions

Name of India's first nuclear reactor is

Assertion : It is not possible to use ${}^{35}Cl$ as the fuel for fusion energy.
Reason : The binding energy of ${}^{35}Cl$ is too small.

What is the approximate power output of a $_{92}U^{235}$ reactor if it consumes $2 \ kg$ of fuel in $30 \ days$ and each fission releases $185 \ MeV$ of usable energy? (Avogadro's number $N_A = 6.02 \times 10^{26} \text{ atoms/kmol}$)

Difficult
View Solution

The binding energy of a deuteron is $2.2 \, MeV$ and the binding energy of $_2^4He$ is $28 \, MeV$. If two deuterons fuse to form a $_2^4He$ nucleus,the energy released is ...... $MeV$.

Consider the $D-T$ reaction (deuterium-tritium fusion):
$_{1}^{2} H +_{1}^{3} H \rightarrow_{2}^{4} He + n$
$(a)$ Calculate the energy released in $MeV$ in this reaction from the data:
$m(_{1}^{2} H) = 2.014102 \; u$
$m(_{1}^{3} H) = 3.016049 \; u$
$(b)$ Consider the radius of both deuterium and tritium to be approximately $2.0 \; fm$. What is the kinetic energy needed to overcome the Coulomb repulsion between the two nuclei? To what temperature must the gas be heated to initiate the reaction?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo